Let the area of the triangle formed by the lines x+2=y-1=z, (x-3)/5=y/-1=(z-1)/1 and x/-3=(y-3)/3=(z-2)/1 be A. Then A^2 is equal to ____

Let the area of the triangle formed by the lines $\displaystyle x+2=y-1=z, \frac{x-3}{5}=\frac{y}{-1}=\frac{z-1}{1}$ and $\displaystyle \frac{x}{-3}=\frac{y-3}{3}=\frac{z-2}{1}$ be $\displaystyle A$. Then $\displaystyle A^2$ is equal to $\displaystyle \_\_\_\_$