Mathematics · 2013
JEE Main · 22 April 2013, Shift 1 · Q87
Let the equations of two ellipses be E_1: x^2/3+y^2/2=1 and E_2: x^2/16+y^2/(b^2)=1. If the product of their eccentricities is 1/2, then the length…
Let the equations of two ellipses be
$\displaystyle \mathrm{E}_1: \frac{x^2}{3}+\frac{y^2}{2}=1$ and
$\displaystyle \mathrm{E}_2: \frac{x^2}{16}+\frac{y^2}{\mathrm{~b}^2}=1$. If the product of their
eccentricities is $\displaystyle \frac{1}{2}$, then the length of the minor axis of ellipse $\displaystyle \mathrm{E}_2$ is :
Official answer
(3)
$\displaystyle 4$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.