Let the eccentricity of an ellipse x^2/(a^2)+y^2/(b^2)=1, a > b, be 1/4. If this ellipse passes through the point (-4 √(2/5), 3), then a^2+ b^2 is…

Let the eccentricity of an ellipse $\displaystyle \frac{x^2}{\mathrm{a}^2}+\frac{y^2}{\mathrm{~b}^2}=1, \mathrm{a}>\mathrm{b}, \mathrm{be} \frac{1}{4}$. If this ellipse passes through the point $\displaystyle \left(-4 \sqrt{\frac{2}{5}}, 3\right)$, then $\displaystyle \mathrm{a}^2+\mathrm{b}^2$ is equal to :