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Mathematics · 2014

JEE Main · 9 April 2014, Shift 1 · Q61

Let P be the relation defined on the set of all real numbers such that P ={( a, b ): sec^2 a - tan^2 b =1}. Then P is:

Let P be the relation defined on the set of all real numbers such that $\displaystyle \mathrm{P}=\left\{(\mathrm{a}, \mathrm{b}): \sec ^2 \mathrm{a}-\tan ^2 \mathrm{~b}=1\right\}$. Then P is :
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.