Mathematics · 2014
JEE Main · 11 April 2014, Shift 1 · Q61
Let f be an odd function defined on the set of real numbers such that for x ≥ 0, f(x)=3 sin x+4 cos x. Then f(x) at x=-(11 π)/6 is equal to:
Let $\displaystyle f$ be an odd function defined on the set of real numbers such that for $\displaystyle x \geqslant 0$,
$\displaystyle f(x)=3 \sin x+4 \cos x$.
Then $\displaystyle f(x)$ at $\displaystyle x=-\frac{11 \pi}{6}$ is equal to:
Official answer
(3)
$\displaystyle \frac{3}{2}-2 \sqrt{3}$
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.