SolveItJEE Main
Mathematics · 2024

JEE Main · 4 April 2024, Shift 2 · Q16

Let P be the point of intersection of the lines (x-2)/1=(y-4)/5=(z-2)/1 and (x-3)/2=(y-2)/3=(z-3)/2. Then, the shortest distance of P from the line 4…

Let P be the point of intersection of the lines $\displaystyle \frac{x-2}{1}=\frac{y-4}{5}=\frac{z-2}{1}$ and $\displaystyle \frac{x-3}{2}=\frac{y-2}{3}=\frac{z-3}{2}$. Then, the shortest distance of P from the line $\displaystyle 4 x=2 y=z$ is
ShareWhatsAppTelegram

More from 3D Geometry

JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.