Mathematics · 2026
JEE Main · 6 April 2026, Shift 1 · Q2
Let one root of the quadratic equation in x: (k^2-15 k+27) x^2+9(k-1) x+18=0 be twice the other. Then the length of the latus rectum of the parabola…
Let one root of the quadratic equation in $\displaystyle x$ :
$\displaystyle \left(k^2-15 k+27\right) x^2+9(k-1) x+18=0$
be twice the other. Then the length of the latus rectum of the parabola $\displaystyle y^2=6 k x$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 12$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.