Mathematics · 2026
JEE Main · 6 April 2026, Shift 2 · Q2
Consider the quadratic equation ( n^2-2 n +2) x^2-3 x+( n^2-2 n +2)^2=0, n ∈ R. Let α be the minimum value of the product of its roots and β be the…
Consider the quadratic equation $\displaystyle \left(\mathrm{n}^2-2 \mathrm{n}+2\right) x^2-3 x+\left(\mathrm{n}^2-2 \mathrm{n}+2\right)^2=0, \mathrm{n} \in \mathbf{R}$. Let $\displaystyle \alpha$ be the minimum value of the product of its roots and $\displaystyle \beta$ be the maximum value of the sum of its roots. Then the sum of the first six terms of the G.P., whose first term is $\displaystyle \alpha$ and the common ratio is $\displaystyle \frac{\alpha}{\beta}$, is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{364}{243}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.