Mathematics · 2026
JEE Main · 6 April 2026, Shift 2 · Q16
Let lim_x → 2 (( tan (x-2))( r x^2+( p -2) x-2 p ))/((x-2)^2)=5 for some r, p ∈ R. If the set of all possible values of q, such that the roots of the…
Let $\displaystyle \lim _{x \rightarrow 2} \frac{(\tan (x-2))\left(\mathrm{r} x^2+(\mathrm{p}-2) x-2 \mathrm{p}\right)}{(x-2)^2}=5$ for some r, $\displaystyle \mathrm{p} \in \mathbf{R}$. If the set of all possible values of q , such that the roots of the equation $\displaystyle \mathrm{r} x^2-\mathrm{p} x+\mathrm{q}=0$ lie in $\displaystyle (0, 2)$, be the interval ( $\displaystyle \alpha, \beta$ ], then $\displaystyle 4(\alpha+\beta)$ equals :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 17$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.