Let a, b ∈ C. Let α, β be the roots of the equation x^2+a x+b=0. If β-α=√ 11 and β^2-α^2=3 i √ 11, then (β^3-α^3)^2 is equal to:

Let $\displaystyle a, b \in \mathbb{C}$. Let $\displaystyle \alpha, \beta$ be the roots of the equation $\displaystyle x^2+a x+b=0$. If $\displaystyle \beta-\alpha=\sqrt{11}$ and $\displaystyle \beta^2-\alpha^2=3 i \sqrt{11}$, then $\displaystyle \left(\beta^3-\alpha^3\right)^2$ is equal to: