Mathematics · 2021
JEE Main · 17 March 2021, Shift 2 · Q80
Let L be a tangent line to the parabola y^2=4 x-20 at (6, 2). If L is also a tangent to the ellipse x^2/2+y^2/b=1, then the value of b is equal to:
Let L be a tangent line to the parabola $\displaystyle y^2=4 x-20$ at $\displaystyle (6, 2)$. If L is also a tangent to the ellipse $\displaystyle \frac{x^2}{2}+\frac{y^2}{\mathrm{~b}}=1$, then the value of b is equal to:
Official answer
(2)
$\displaystyle 14$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.