Mathematics · 2024
JEE Main · 6 April 2024, Shift 2 · Q6
Let 0 ≤ r ≤ n. If ^n+1 C_r+1:^n C_r:^n-1 C_r-1=55: 35: 21, then 2 n+5 r is equal to:
Let $\displaystyle 0 \leq r \leq n$. If $\displaystyle { }^{n+1} C_{r+1}:{ }^n C_r:{ }^{n-1} C_{r-1}=55: 35: 21$, then $\displaystyle 2 n+5 r$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 50$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.