Mathematics · 2024
JEE Main · 6 April 2024, Shift 1 · Q23
If the second, third and fourth terms in the expansion of (x+y)^n are 135, 30 and 10/3, respectively, then 6(n^3+x^2+y) is equal to ____
If the second, third and fourth terms in the expansion of $\displaystyle (x+y)^n$ are $\displaystyle 135$, $\displaystyle 30$ and $\displaystyle \frac{10}{3}$, respectively, then $\displaystyle 6\left(n^3+x^2+y\right)$ is equal to $\displaystyle \_\_\_\_$
Official answer
From NTA’s final answer key for this paper.
806
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.