Mathematics · 2022
JEE Main · 29 July 2022, Shift 2 · Q10
Let y=y(x) be the solution curve of the differential equation (d y)/(d x)+((2 x^2+11 x+13)/(x^3+6 x^2+11 x+6)) y=((x+3))/(x+1), x>-1, which passes…
Let $\displaystyle y=y(x)$ be the solution curve of the differential equation $\displaystyle \frac{d y}{d x}+\left(\frac{2 x^2+11 x+13}{x^3+6 x^2+11 x+6}\right) y=\frac{(x+3)}{x+1}, x>-1$, which passes through the point $\displaystyle (0,1)$. Then $\displaystyle y(1)$ is equal to :
Official answer
(2)
$\displaystyle \frac{3}{2}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.