Mathematics · 2022
JEE Main · 29 July 2022, Shift 2 · Q9
If the solution curve of the differential equation (d y)/(d x)=(x+y-2)/(x-y) passes through the points (2,1) and ( k +1,2), k >0, then
If the solution curve of the differential equation $\displaystyle \frac{d y}{d x}=\frac{x+y-2}{x-y}$ passes through the points $\displaystyle (2,1)$ and $\displaystyle (\mathrm{k}+1,2), \mathrm{k}>0$, then
Official answer
(1)
$\displaystyle 2 \tan ^{-1}\left(\frac{1}{k}\right)=\log _e\left(k^2+1\right)$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.