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Mathematics · 2019

JEE Main · 10 January 2019, Shift 2 · Q61

Let N be the set of natural numbers and two functions f and g be defined as f, g: N → N such that f( n )= {(n +1)/2, if n is odd; n/2, if n is even}…

Let $\displaystyle \mathbf{N}$ be the set of natural numbers and two functions $\displaystyle f$ and $\displaystyle g$ be defined as $\displaystyle f, g: \mathbf{N} \rightarrow \mathbf{N}$ such that $$f(\mathrm{n})=\left\{\begin{array}{cl} \frac{\mathrm{n}+1}{2} & \text { if } \mathrm{n} \text { is odd } \\ \frac{\mathrm{n}}{2} & \text { if } \mathrm{n} \text { is even } \end{array}\right. $$ and $\displaystyle g(\mathbf{n})=\mathbf{n}-(-1)^{\mathbf{n}}$. Then $\displaystyle f \circ g$ is :
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.