Mathematics · 2021
JEE Main · 27 August 2021, Shift 2 · Q61
Let Z be the set of all integers, A ={(x, y) ∈ Z × Z:(x-2)^2+y^2 ≤ 4}, B ={(x, y) ∈ Z × Z: x^2+y^2 ≤ 4} and C ={(x, y) ∈ Z × Z:(x-2)^2+(y-2)^2 ≤ 4}…
Let $\displaystyle \mathbb{Z}$ be the set of all integers,
$$\begin{aligned}
& \mathrm{A}=\left\{(x, y) \in \mathbb{Z} \times \mathbb{Z}:(x-2)^2+y^2 \leq 4\right\}, \\
& \mathrm{B}=\left\{(x, y) \in \mathbb{Z} \times \mathbb{Z}: x^2+y^2 \leq 4\right\} \text { and } \\
& \mathrm{C}=\left\{(x, y) \in \mathbb{Z} \times \mathbb{Z}:(x-2)^2+(y-2)^2 \leq 4\right\}
\end{aligned}
$$
If the total number of relations from $\displaystyle \mathrm{A} \cap \mathrm{B}$ to $\displaystyle \mathrm{A} \cap \mathrm{C}$ is $\displaystyle 2^{\mathrm{p}}$, then the value of p is :
Official answer
(3)
$\displaystyle 25$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.