Mathematics · 2019
JEE Main · 11 January 2019, Shift 1 · Q61
Let f: R → R be defined by f(x)=x/(1+x^2), x ∈ R. Then the range of f is:
Let $\displaystyle f: \mathbf{R} \rightarrow \mathbf{R}$ be defined by $\displaystyle f(x)=\frac{x}{1+x^2}$,
$\displaystyle x \in \mathbf{R}$. Then the range of $\displaystyle f$ is :
Official answer
(4)
$\displaystyle \left[-\frac{1}{2}, \frac{1}{2}\right]$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.