Mathematics · 2025
JEE Main · 7 April 2025, Shift 2 · Q18
Let f: R → R be a polynomial function of degree four having extreme values at x=4 and x=5. If lim_x → 0 (f(x))/x^2=5, then f(2) is equal to:
Let $\displaystyle f: \mathbf{R} \rightarrow \mathbf{R}$ be a polynomial function of degree four having extreme values at $\displaystyle x=4$ and $\displaystyle x=5$. If $\displaystyle \lim _{x \rightarrow 0} \frac{f(x)}{x^2}=5$, then $\displaystyle f(2)$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 10$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.