Mathematics · 2023
JEE Main · 1 February 2023, Shift 2 · Q66
Let f: R -{0,1} → R be a function such that f(x)+f(1/(1-x))=1+x. Then f(2) is equal to
Let $\displaystyle f: \mathbb{R}-\{0,1\} \rightarrow \mathbb{R}$ be a function such that $\displaystyle f(x)+f\left(\frac{1}{1-x}\right)=1+x$. Then $\displaystyle f(2)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{9}{4}$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.