Mathematics · 2024
JEE Main · 4 April 2024, Shift 1 · Q6
Let f: R → R be a function given by f(x)= {(1- cos 2 x)/x^2, x<0; α, x=0, (β √(1- cos x))/x, x>0} where α, β ∈ R. If f is continuous at x=0, then…
Let $\displaystyle f: \mathbf{R} \rightarrow \mathbf{R}$ be a function given by
$$f(x)=\left\{\begin{array}{cc}
\frac{1-\cos 2 x}{x^2}, & x<0 \\
\alpha, & x=0, \\
\frac{\beta \sqrt{1-\cos x}}{x}, & x>0
\end{array}\right.
$$
where $\displaystyle \alpha, \beta \in \mathbf{R}$. If $\displaystyle f$ is continuous at $\displaystyle x=0$, then $\displaystyle \alpha^2+\beta^2$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 12$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.