Mathematics · 2024
JEE Main · 4 April 2024, Shift 2 · Q8
If the function f(x)= {(72^x-9^x-8^x+1)/(√ 2 -√(1+ cos x)), x ≠ 0; a log_e 2 log_e 3, x=0} is continuous at x=0, then the value of a^2 is equal to
If the function
$$f(x)= \begin{cases}\frac{72^x-9^x-8^x+1}{\sqrt{2}-\sqrt{1+\cos x}}, & x \neq 0 \\ a \log _e 2 \log _e 3, & x=0\end{cases}
$$
is continuous at $\displaystyle x=0$, then the value of $\displaystyle a^2$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 1152$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.