Mathematics · 2024
JEE Main · 30 January 2024, Shift 1 · Q30
If the function f(x)= {1/(|x|), |x| ≥ 2; a x^2+2 b, |x|<2} is differentiable on R, then 48( a + b ) is equal to ____.
If the function
$$f(x)= \begin{cases}\frac{1}{|x|}, & |x| \geqslant 2 \\ a x^2+2 b, & |x|<2\end{cases}
$$
is differentiable on $\displaystyle \mathbf{R}$, then $\displaystyle 48(\mathrm{a}+\mathrm{b})$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
15
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.