Mathematics · 2024
JEE Main · 6 April 2024, Shift 1 · Q8
If f(x)= {x^3 sin (1/x), x ≠ 0; 0, x=0}, then
If $\displaystyle f(x)=\left\{\begin{array}{ll}x^3 \sin \left(\frac{1}{x}\right), & x \neq 0 \\ 0, & x=0\end{array}\right.$, then
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle f^{\prime \prime}\left(\frac{2}{\pi}\right)=\frac{24-\pi^2}{2 \pi}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.