Mathematics · 2020
JEE Main · 8 January 2020, Shift 2 · Q51
Let f:(1,3) → R be a function defined by f(x)=(x[x])/(1+x^2), where [x] denotes the greatest integer ≤ x. Then the range of f is:
Let $\displaystyle f:(1,3) \rightarrow \mathbf{R}$ be a function defined by $\displaystyle f(x)=\frac{x[x]}{1+x^2}$, where $\displaystyle [x]$ denotes the greatest integer $\displaystyle \leq x$. Then the range of $\displaystyle f$ is :
Official answer
(3)
$\displaystyle \left(\frac{2}{5}, \frac{1}{2}\right) \cup\left(\frac{3}{5}, \frac{4}{5}\right]$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.