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Mathematics · 2022

JEE Main · 25 June 2022, Shift 1 · Q27

Let f: R → R be a function defined by f(x)=(2(1-(x^25)/2)(2+x^25))^(1/50). If the function g(x)=f(f(f(x)))+f(f(x)), then the greatest integer less…

Let $\displaystyle f: \mathbf{R} \rightarrow \mathbf{R}$ be a function defined by $\displaystyle f(x)=\left(2\left(1-\frac{x^{25}}{2}\right)\left(2+x^{25}\right)\right)^{\frac{1}{50}}$. If the function $\displaystyle g(x)=f(f(f(x)))+f(f(x))$, then the greatest integer less than or equal to $\displaystyle g(1)$ is \_\_\_\_.
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.