Mathematics · 2018
JEE Main · 15 April 2018, Shift 2 · Q61
Let f: A → B be a function defined as f(x)=(x-1)/(x-2), where A = R -{2} and B = R -{1}. Then f is:
Let $\displaystyle f: \mathrm{A} \rightarrow \mathrm{B}$ be a function defined as $\displaystyle f(x)=\frac{x-1}{x-2}$, where $\displaystyle \mathrm{A}=\mathbf{R}-\{2\}$ and $\displaystyle \mathrm{B}=\mathbf{R}-\{1\}$. Then $\displaystyle f$ is :
Official answer
(2)
invertible and $\displaystyle f^{-1}(y)=\frac{2 y-1}{y-1}$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.