Mathematics · 2020
JEE Main · 4 September 2020, Shift 2 · Q66
Let x=4 be a directrix to an ellipse whose centre is at the origin and its eccentricity is 1/2. If P (1, β), β>0 is a point on this ellipse, then the…
Let $\displaystyle x=4$ be a directrix to an ellipse whose centre is at the origin and its eccentricity is $\displaystyle \frac{1}{2}$. If $\displaystyle \mathrm{P}(1, \beta), \beta>0$ is a point on this ellipse, then the equation of the normal to it at P is :
Official answer
(2)
$\displaystyle 4 x-2 y=1$
More from Ellipse
- Let the line y-x=1 intersect the ellipse x^2/2+y^2/1=1 at the points A and B. Then the angle made by the line segment AB at the center of the ellipse…2026
- If α x+β y=109 is the equation of the chord of the ellipse x^2/9+y^2/4=1, whose mid point is (5/2, 1/2), then α+β is equal to:2025
- Let an ellipse with centre (1,0) and latus rectum of length 1/2 have its major axis along x -axis. If its minor axis subtends an angle 60^° at the…2023
- Let L be a common tangent line to the curves 4 x^2+9 y^2=36 and (2 x)^2+(2 y)^2=31. Then the square of the slope of the line L is \ \ \ \.2021
- Let (h, k) lie on the circle C: x^2+y^2=4 and the point (2 h+1,3 k+2) lie on an ellipse with eccentricity e. Then the value of 5/e^2 is equal to ____.2026
- The equation of the chord, of the ellipse x^2/25+y^2/16=1, whose mid-point is (3,1) is:2025
- The locus of mid-points of the line segments joining (-3, -5) and the points on the ellipse x^2/4+y^2/9=1 is:2021
- The length of the latus-rectum of the ellipse, whose foci are (2,5) and (2,-3) and eccentricity is 4/5, is2025
JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.