Mathematics · 2024
JEE Main · 9 April 2024, Shift 2 · Q2
Let z be a complex number such that the real part of (z-2 i)/(z+2 i) is zero. Then, the maximum value of |z-(6+8 i)| is equal to
Let $\displaystyle z$ be a complex number such that the real part of $\displaystyle \frac{z-2 i}{z+2 i}$ is zero. Then, the maximum value of $\displaystyle |z-(6+8 i)|$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 12$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.