Let S_1={z ∈ C:|z| ≤ 5}, S_2={z ∈ C: Im ((z+1-√ 3 i)/(1-√ 3 i)) ≥ 0} and S_3={z ∈ C: Re (z) ≥ 0}. Then the area of the region S_1 ∩ S_2 ∩ S_3 is:

Let $\displaystyle S_1=\{z \in C:|z| \leq 5\}, S_2=\left\{z \in C: \operatorname{Im}\left(\frac{z+1-\sqrt{3} i}{1-\sqrt{3} i}\right) \geq 0\right\}$ and $\displaystyle S_3=\{z \in C: \operatorname{Re}(z) \geq 0\}$. Then the area of the region $\displaystyle S_1 \cap S_2 \cap S_3$ is: