Mathematics · 2023
JEE Main · 1 February 2023, Shift 1 · Q69
Let f(x)=2 x+ tan^-1 x and g(x)= log_e(√(1+x^2)+x), x ∈[0,3]. Then
Let $\displaystyle f(x)=2 x+\tan ^{-1} x$ and $\displaystyle g(x)=\log _e\left(\sqrt{1+x^2}+x\right), x \in[0,3]$.
Then
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \max f(x)>\max g(x)$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.