Mathematics · 2023
JEE Main · 31 January 2023, Shift 2 · Q68
The absolute minimum value, of the function f(x)=|x^2-x+1|+[x^2-x+1], where [t] denotes the greatest integer function, in the interval [-1,2], is:
The absolute minimum value, of the function $\displaystyle f(x)=\left|x^2-x+1\right|+\left[x^2-x+1\right]$, where $\displaystyle [t]$ denotes the greatest integer function, in the interval $\displaystyle [-1,2]$, is:
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{3}{4}$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.