Mathematics · 2023
JEE Main · 1 February 2023, Shift 2 · Q69
The sum of the absolute maximum and minimum values of the function f(x)=|x^2-5 x+6|-3 x+2 in the interval [-1,3] is equal to:
The sum of the absolute maximum and minimum values of the function $\displaystyle f(x)=\left|x^2-5 x+6\right|-3 x+2$ in the interval $\displaystyle [-1,3]$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 10$
More from Applications of Derivatives
- Let the function f(x)=x/3+3/x+3, x ≠ 0 be strictly increasing in (-∞, α_1) ∪(α_2, ∞) and strictly decreasing in (α_3, α_4) ∪(α_4, α_5). Then Σ_i=1^5…2025
- Let f:(0,1) → R be a function defined by f(x)=1/(1-e^-x), and g(x)=(f(-x)-f(x)). Consider two statements (I) g is an increasing function in (0,1)…2023
- A wire of length 20 m is to be cut into two pieces. A piece of length l_1 is bent to make a square of area A_1 and the other piece of length l_2 is…2023
- Let f(x)=2 x+ tan^-1 x and g(x)= log_e(√(1+x^2)+x), x ∈[0,3]. Then2023
- If the function f(x)=2 x^3-9 a x^2+12 a^2 x+1, where a>0, attains its local maximum and local minimum values at p and q, respectively, such that…2025
- The number of critical points of the function f(x)=(x-2)^2 / 3(2 x+1) is2024
- Let f: R → R be a twice differentiable function such that f^′ ′(x)>0 for all x ∈ R and f^′(a-1)=0, where a is a real number. Let g(x)=f( tan^2 x-2…2026
- For the function f(x)=( cos x)-x+1, x ∈ R, between the following two statements (S1) f(x)=0 for only one value of x in [0, π]. (S2) f(x) is…2024
JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.