Mathematics · 2021
JEE Main · 26 February 2021, Shift 2 · Q69
Let f(x)= sin^-1 x and g(x)=(x^2-x-2)/(2 x^2-x-6). If g(2)= lim_x → 2 g(x), then the domain of the function f o g is:
Let $\displaystyle f(x)=\sin ^{-1} x$ and $\displaystyle g(x)=\frac{x^2-x-2}{2 x^2-x-6}$. If $\displaystyle g(2)=\lim _{x \rightarrow 2} g(x)$, then the domain of the function $\displaystyle f o g$ is :
Official answer
(2)
$\displaystyle (-\infty,-2] \cup\left[-\frac{4}{3}, \infty\right)$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.