Let f(x)=x^2+9, g(x)=x/(x-9) and a =f ° g(10), b =g ° f(3). If e and l denote the eccentricity and the length of the latus rectum of the ellipse…

Let $\displaystyle f(x)=x^2+9, g(x)=\frac{x}{x-9}$ and $\displaystyle \mathrm{a}=f \circ g(10), \mathrm{b}=g \circ f(3)$. If e and $\displaystyle l$ denote the eccentricity and the length of the latus rectum of the ellipse $\displaystyle \frac{x^2}{a}+\frac{y^2}{b}=1$, then $\displaystyle 8 e^2+l^2$ is equal to.