Mathematics · 2024
JEE Main · 4 April 2024, Shift 1 · Q2
Let α and β be the sum and the product of all the non-zero solutions of the equation (z̄)^2+|z|=0, z ∈ C. Then 4(α^2+β^2) is equal to:
Let $\displaystyle \alpha$ and $\displaystyle \beta$ be the sum and the product of all the non-zero solutions of the equation $\displaystyle (\bar{z})^2+|z|=0$, $\displaystyle z \in C$. Then $\displaystyle 4\left(\alpha^2+\beta^2\right)$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 4$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.