Mathematics · 2019
JEE Main · 10 April 2019, Shift 1 · Q83
Let A(3, 0, - 1), B(2, 10, 6) and C(1, 2, 1) be the vertices of a triangle and M be the midpoint of AC. If G divides BM in the ratio, 2: 1, then cos…
Let A($\displaystyle 3$, $\displaystyle 0$, - $\displaystyle 1$), B($\displaystyle 2$, $\displaystyle 10$, $\displaystyle 6$) and C($\displaystyle 1$, $\displaystyle 2$, $\displaystyle 1$) be the vertices of a triangle and M be the midpoint of AC. If G divides BM in the ratio, $\displaystyle 2$ : $\displaystyle 1$, then $\displaystyle \cos (\angle \mathrm{GOA})$ (O being the origin) is equal to :
Official answer
(1)
$\displaystyle \frac{1}{\sqrt{15}}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.