Mathematics · 2019
JEE Main · 10 April 2019, Shift 1 · Q84
If Q (0,-1,-3) is the image of the point P in the plane 3 x-y+4 z=2 and R is the point (3, -1, -2), then the area (in sq. units) of PQR is:
If $\displaystyle \mathrm{Q}(0,-1,-3)$ is the image of the point P in the plane $\displaystyle 3 x-y+4 z=2$ and R is the point ($\displaystyle 3$, -$\displaystyle 1$, -$\displaystyle 2$), then the area (in sq. units) of $\displaystyle \triangle \mathrm{PQR}$ is :
Official answer
(4)
$\displaystyle \frac{\sqrt{91}}{2}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.