Mathematics · 2021
JEE Main · 24 February 2021, Shift 1 · Q66
lim_x → 0 (∫_0^x^2( sin √ t ) d t)/x^3 is equal to:
$\displaystyle \lim _{x \rightarrow 0} \frac{\int_0^{x^2}(\sin \sqrt{t}) d t}{x^3}$ is equal to :
Official answer
(1)
$\displaystyle \frac{2}{3}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.