Mathematics · 2021
JEE Main · 25 February 2021, Shift 1 · Q66
lim_n → ∞ (1+(1+1/2+… ….+1/n)/(n^2))^n is equal to:
$\displaystyle \lim _{\mathrm{n} \rightarrow \infty}\left(1+\frac{1+\dfrac{1}{2}+\ldots \ldots .+\dfrac{1}{\mathrm{n}}}{\mathrm{n}^2}\right)^{\mathrm{n}}$ is equal to :
Official answer
(4)
$\displaystyle 1$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.