Mathematics · 2025
JEE Main · 24 January 2025, Shift 2 · Q6
If 7=5+1/7(5+α)+1/7^2(5+2 α)+1/7^3(5+3 α)+… … ….. ∞, then the value of α is:
If $\displaystyle 7=5+\frac{1}{7}(5+\alpha)+\frac{1}{7^2}(5+2 \alpha)+\frac{1}{7^3}(5+3 \alpha)+\ldots \ldots \ldots . . \infty$, then the value of $\displaystyle \alpha$ is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 6$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.