Mathematics · 2025
JEE Main · 24 January 2025, Shift 2 · Q7
In an arithmetic progression, if S_40=1030 and S_12=57, then S_30- S_10 is equal to:
In an arithmetic progression, if $\displaystyle \mathrm{S}_{40}=1030$ and $\displaystyle \mathrm{S}_{12}=57$, then $\displaystyle \mathrm{S}_{30}-\mathrm{S}_{10}$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 515$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.