Mathematics · 2026
JEE Main · 28 January 2026, Shift 2 · Q5
6/(3^26)+(10 · 1)/(3^25)+(10 · 2)/(3^24)+(10 · 2^2)/(3^23)+…+(10 · 2^24)/3 is equal to:
$\displaystyle \frac{6}{3^{26}}+\frac{10 \cdot 1}{3^{25}}+\frac{10 \cdot 2}{3^{24}}+\frac{10 \cdot 2^2}{3^{23}}+\ldots+\frac{10 \cdot 2^{24}}{3}$ is equal to $\displaystyle :$
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 2^{26}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.