Mathematics · 2025
JEE Main · 28 January 2025, Shift 1 · Q6
Let T_r be the r^th term of an A.P. If for some m, T_m =1/25, T_25=1/20, and 20 Σ_r =1^25 T_r =13, then 5 m Σ_r = m^2 m T_r is equal to
Let $\displaystyle \mathrm{T}_{\mathrm{r}}$ be the $\displaystyle \mathrm{r}^{\text {th }}$ term of an A.P. If for some $\displaystyle \mathrm{m}, \mathrm{T}_{\mathrm{m}}=\frac{1}{25}, \mathrm{~T}_{25}=\frac{1}{20}$, and $\displaystyle 20 \sum_{\mathrm{r}=1}^{25} \mathrm{~T}_{\mathrm{r}}=13$, then $\displaystyle 5 \mathrm{~m} \sum_{\mathrm{r}=\mathrm{m}}^{2 \mathrm{~m}} \mathrm{~T}_{\mathrm{r}}$ is equal to
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 126$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.