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Mathematics · 2023

JEE Main · 24 January 2023, Shift 2 · Q61

If f(x)=(2^2 x)/(2^2 x+2), x ∈ R, then f(1/2023)+f(2/2023)+…+f(2022/2023) is equal to

If $\displaystyle f(x)=\frac{2^{2 x}}{2^{2 x}+2}, x \in \mathbb{R}$, then $\displaystyle f\left(\frac{1}{2023}\right)+f\left(\frac{2}{2023}\right)+\ldots+f\left(\frac{2022}{2023}\right)$ is equal to
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.