Mathematics · 2015
JEE Main · 10 April 2015, Shift 1 · Q89
If f(x)=2 tan^-1 x+ sin^-1((2 x)/(1+x^2)), x>1, then f(5) is equal to:
If $\displaystyle f(x)=2 \tan ^{-1} x+\sin ^{-1}\left(\frac{2 x}{1+x^2}\right), x>1$, then $\displaystyle f(5)$ is equal to :
Official answer
(2)
$\displaystyle \pi$
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.