Mathematics · 2026
JEE Main · 23 January 2026, Shift 2 · Q4
If z=(√ 3)/2+i/2, i=√ -1, then (z^201-i)^8 is equal to
If $\displaystyle z=\frac{\sqrt{3}}{2}+\frac{i}{2}, i=\sqrt{-1}$, then $\displaystyle \left(z^{201}-i\right)^8$ is equal to
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 256$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.