Mathematics · 2013
JEE Main · 22 April 2013, Shift 1 · Q79
If ∫ (x^2-x+1)/(x^2+1) e^cot^-1 x d x= A (x) e^cot^-1 x + C, then A (x) is equal to:
If $\displaystyle \int \frac{x^2-x+1}{x^2+1} \mathrm{e}^{\cot ^{-1} x} \mathrm{~d} x=\mathrm{A}(x) \mathrm{e}^{\cot ^{-1} x}+\mathrm{C}$, then $\displaystyle \mathrm{A}(x)$ is equal to :
Official answer
(2)
$\displaystyle x$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.