Mathematics · 2015
JEE Main · 11 April 2015, Shift 1 · Q74
If ∫ (log ( t +√(1+ t^2)))/(√(1+ t^2)) dt =1/2( g ( t ))^2+ C, where C is a constant, then g(2) is equal to:
If $\displaystyle \int \frac{\log \left(\mathrm{t}+\sqrt{1+\mathrm{t}^2}\right)}{\sqrt{1+\mathrm{t}^2}} \mathrm{dt}=\frac{1}{2}(\mathrm{~g}(\mathrm{t}))^2+\mathrm{C}$, where $\displaystyle C$ is a constant, then $\displaystyle g(2)$ is equal to :
Official answer
(2)
$\displaystyle \log (2+\sqrt{5})$
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.