Mathematics · 2014
JEE Main · 11 April 2014, Shift 1 · Q75
The integral ∫ x cos^-1((1-x^2)/(1+x^2)) d x(x>0) is equal to:
The integral $\displaystyle \int x \cos ^{-1}\left(\frac{1-x^2}{1+x^2}\right) \mathrm{d} x(x>0)$ is equal to :
Official answer
(1)
$\displaystyle -x+\left(1+x^2\right) \tan ^{-1} x+c$
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.